Mathematics · Differential Equations
The solution of the simultaneous differential equation dxz(x+y) = dyz(x-y) = dzx2+y2 is:
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- 1x2 + y2 - z2 = c1 and 2xy - y2 = c2
- 2x2 - y2 - z2 = c1 and 2xz - y2 = c2
- 3x2 + y2 + z2 = c1 and xyz = c2
- 4x2 - y2 - z2 = c1 and 2xy - z2 = c2✓
Correct answer
x2 - y2 - z2 = c1 and 2xy - z2 = c2
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