Mathematics · Differential Equations
The solution of the differential equation (y+z)p + (z+x)q = x+y is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1φ((x−y)/(x−z), (x−y)2(x+y+z)) = 0✓
- 2φ((x−y)/(x−z), (x+y)2(x+y+z)) = 0
- 3φ((x−y)/(x−z), (x+y+z)) = 0
- 4φ((x−y)/(x−z), xyz) = 0
Correct answer
φ((x−y)/(x−z), (x−y)2(x+y+z)) = 0
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