Mathematics · Differential Equations
The solution of the differential equation x2(y + 1)dydx + y2(x + 1)2 = 0, when y(1) = 2, is:
- 1log|13 x2y| = 1x + 1y - x + 12
- 2log|12 x2y| = 1x + 1y - x - 12✓
- 3log|14 x2y| = 1x + 2y + x - 1
- 4log|x2y| = 2x + 1y + x - 1
Correct answer
log|12 x2y| = 1x + 1y - x - 12
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