Mathematics · Differential Equations
The solution of the differential equation x log(x) dy dx + y = 4 log(x) is:
- 1y = 4 log(x) + c/(4 log(x)), where c is an arbitrary constant
- 2y = 4 log(x) + c/log(x), where c is an arbitrary constant
- 3y = log(x) + c/log(x), where c is an arbitrary constant
- 4y = 2 log(x) + c/log(x), where c is an arbitrary constant✓
Correct answer
y = 2 log(x) + c/log(x), where c is an arbitrary constant
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