Mathematics · Differential Equations
The solution of the differential equation loge(dydx) = 2x - y, with y(0) = 0, is:
- 1ey = 2e2x + 1
- 22ey = e2x + 1✓
- 3ey = 2e2x + 3
- 42ey = e2x - 1
Correct answer
2ey = e2x + 1
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