Mathematics · Differential Equations
The solution of the differential equation dydx + 2xy1 + x2 = 1(1 + x2)2 is:
- 1y(1 + x2) = c + tan-1x✓
- 2y1 + x2 = c + tan-1x
- 3y log (1 + x2) = c + tan-1x
- 4y (1 + x2) = c + sin-1x
Correct answer
y(1 + x2) = c + tan-1x
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