Mathematics · Differential Equations
The solution of the differential equation d2ydx2 - 2y3 - 2y = 0, given the initial conditions y(0) = 0 and y'(0) = 1, is:
- 1y = cot(x)
- 2y = tan(x)✓
- 3y = tan(x) + 1
- 4y = cot(x) + 1
Correct answer
y = tan(x)
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