Mathematics · Differential Equations
The solution of the differential equation (1 + x2)dydx + 2xy - 4x2 = 0 with initial condition y(0) = 0 is:
- 1y = 4x33(1 + x2)✓
- 2y = (1 + x)3/2 + 2x
- 3y = 11 + x2 + sin-1x
- 4y = 12(1 + x2)
Correct answer
y = 4x33(1 + x2)
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