Mathematics · Differential Equations
The solution for the differential equation log(dydx) = 3x + 4y is:
- 13e4y + 4e-3x + C = 0
- 2e3x+4y + C = 0
- 33e-3y + 4e4x + 12C = 0
- 43e-4y + 4e-3x + C = 0✓
Correct answer
3e-4y + 4e-3x + C = 0
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