Mathematics · Differential Equations
The solution curve of the differential equation (1 + e-x)(1 + y2) dydx = y2 which passes through the point (0, 1) is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1y2 = 1 + y loge((1 + e-x)/2)
- 2y2 = 1 + y loge((1 + ex)/2)
- 3y2 + 1 = y (loge((1 + ex)/2) + 2)✓
- 4y2 + 1 = y (loge((1 + e-x)/2) + 2)
Correct answer
y2 + 1 = y (loge((1 + ex)/2) + 2)
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