Mathematics · Strength of Materials
The section modulus (Z) of a hollow circular section with external diameter 'D' and internal diameter 'd' is given by which expression?
- 1Z = (π/30D) [D4 - d4]
- 2Z = (π/32D) [D4 - d4]✓
- 3Z = (π/16D) [D4 - d4]
- 4Z = (π/32D) [D2 - d2]
Correct answer
Z = (π/32D) [D4 - d4]
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