Chemistry · Chemical Kinetics
The rate law for a reaction between substances A and B is given by Rate = k[A]n[B]m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be:
- 112(m + n)
- 22(n − m)✓
- 3(n − m)
- 4(m + n)
Correct answer
2(n − m)
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