Mathematics · Probability
The probability that a ticketless traveler is caught during a single trip is 0.1. If the traveler makes 4 independent trips, the probability that he/she will be caught during at least one of the trips is:
- 1(0.9)4
- 21 - (1 - 0.9)4
- 3(1 - 0.9)4
- 41 - (0.9)4✓
Correct answer
1 - (0.9)4
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