Chemistry · Chemical Kinetics
The predicted rate law, using the steady-state approximation, for the reaction H 2 O 2 + 2H + + 2I - → I 2 + 2H 2 O following the mechanism: H + + I - k 1 k -1 HI (rapid equilibrium) HI + H 2 O 2 → H 2 O + HOI (slow, rate constant k 2 ) HOI + I - → I 2 + OH - (fast, rate constant k 3 ) OH - + H + → H 2 O (fast, rate constant k 4 ) is given by:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1k 2 k 1 k -1 k 4 [H + ][I - ][H 2 O 2 ]
- 2k 1 k -1 k 2 [HI][H 2 O 2 ]
- 3k 2 [HI][H 2 O 2 ]
- 4k 1 k 2 [H + ][I - ][H 2 O 2 ] k -1 + k 2 [H 2 O 2 ]✓
Correct answer
k 1 k 2 [H + ][I - ][H 2 O 2 ] k -1 + k 2 [H 2 O 2 ]
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