Mathematics · Chemical Kinetics
The pre-exponential factors of two different reactions of the same order are identical. The activation energy of the first reaction exceeds the activation energy of the second reaction by 20 kJ mol-1. If k1 and k2 are the rate constants of the first and second reactions respectively at 300 K, then the value of lnk2k1 (rounded off to the nearest integer) is: (Given R = 8.3 J K-1 mol-1)
- 110
- 28✓
- 36
- 44
Correct answer
8
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Chemical Kinetics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Chemical Kinetics