Chemistry · Chemical Kinetics
The pre-exponential factors of two different reactions of the same order are identical. The activation energy of the first reaction exceeds that of the second reaction by 25 kJ mol-1. If k1 and k2 are the rate constants of the first and second reactions respectively at 350 K, then the value of ln(k2/k1) is nearest to (R = 8.3 J K-1 mol-1):
- 112
- 23
- 36
- 49✓
Correct answer
9
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