Physics · Work, Energy and Power
The potential energy function for a particle executing linear simple harmonic motion (SHM) is given by V(x) = 12kx2, where k is the force constant of the oscillator. A particle of total energy E turns back when it reaches x = ±xm. If V and K indicate the potential energy and kinetic energy respectively of the particle at x = +xm, then which of the following is correct?
- 1V = 0, K < E
- 2V < E, K = 0
- 3V = E, K = 0✓
- 4V = 0, K = E
Correct answer
V = E, K = 0
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