Mathematics · Differential Equations
The particular solution of the differential equation (1 + log x) dxdy - x log x = 0 when x = e, y = e2 is:
- 1y = x log x + e2
- 2xy = e log x - e + e3✓
- 3ey = x log x + e3 - e
- 4y = log(x log x) + (e2 - 1)
Correct answer
xy = e log x - e + e3
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Differential Equations?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Differential Equations