Physics · Laws of Motion
The open parachute of a parachutist experiences due to air friction, a negative acceleration, besides the acceleration due to gravity: a = -b × v2 where b = 0.2 m-1. His constant final velocity (in m/s) will be (take g = 9.8 m/s2):
- 1Zero
- 29.8
- 37.0✓
- 44.9
Correct answer
7.0
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