Computer · Mechanics of Materials

The moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its center of gravity (C.G.) and parallel to the base is:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

1bh336✓
2bh312
3bh38
4bh34

Correct answer

bh336

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The moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its center of gravity (C.G.) and parallel to the base is:

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The moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its center of gravity (C.G.) and parallel to the base is:

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