Physics · Rotational Motion
The moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is I. If the same rod is bent into a ring and its moment of inertia about its diameter is I', then the ratio I/I' is:
- 1(3/2)π2
- 2(5/3)π2
- 3(2/3)π2
- 4(8/3)π2✓
Correct answer
(8/3)π2
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