Mathematics · Coordinate Geometry
The locus of the third vertex of a right-angled triangle, the ends of whose hypotenuse are (1, 2) and (4, 5), is:
- 1x2 + y2 - 5x - 7y + 14 = 0✓
- 23x + 3y + 1 = 0
- 33x + 3y - 1 = 0
- 4x2 + y2 + 5x + 7y + 14 = 0
Correct answer
x2 + y2 - 5x - 7y + 14 = 0
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