Mathematics · Integrals
The integral ∫ dx(x+4)8/7(x-3)6/7 is equal to: (where C is a constant of integration)
- 1-113(x - 3x + 4)-13/7 + C
- 212(x - 3x + 4)3/7 + C
- 3(x - 3x + 4)-1/7 + C
- 4(x - 3x + 4)1/7 + C✓
Correct answer
(x - 3x + 4)1/7 + C
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