Mathematics · Calculus and Series
The integral ∫01 ( ∑n=1∞ xnn2 ) dx is equal to:
- 1∑n=1∞ 1n2
- 2∑n=1∞ 1n2(n + 1)✓
- 3∑n=1∞ 1n(n + 1)
- 4∑n=1∞ 1n2(n2 + 1)
Correct answer
∑n=1∞ 1n2(n + 1)
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