Mathematics · Trigonometric Equations
The general solution of the equation sin 2 θ sec θ + √3 tan θ = 0 is:
- 1θ = nπ + (-1) n+1 · π 3
- 2θ = nπ✓
- 3θ = nπ + (-1) n+1 · π 6
- 4θ = nπ 2 , where n ∈ Z
Correct answer
θ = nπ
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