Mathematics · Differential Equations
The general solution of the differential equation xy(y + 2)dy + (y3 - 1) dx = 0 is
- 1log |x + 2y| + (2/√3) Tan-1 ((y - x) / (√3x)) = c
- 2log |2x - y| + (2/3) Tan-1 ((x - y) / (√3x)) = c
- 3log |xy - x| + (2/√3) Tan-1 ((2y + 1) / √3) = c✓
- 4log |x + y| + (2/3) Tan-1 ((x - 2y) / (√3x)) = c
Correct answer
log |xy - x| + (2/√3) Tan-1 ((2y + 1) / √3) = c
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