Mathematics · Differential Equations
The general solution of the differential equation sec2y dydx + 2x tan y = x3 is:
- 1tan y = ce-x2 + 12(x2 + 1)
- 2tan y = ce-x2 + 12(x2 - 1)✓
- 3tan y = cex2 + 12(x2 - 1)
- 4tan y = ce-x2 + x2 - 1
Correct answer
tan y = ce-x2 + 12(x2 - 1)
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