Mathematics · Differential Equations
The general solution of the differential equation (ex + 1)y dy = (y + 1) ex dx is:
- 1y = log {ex + 1y + 1} + k
- 2y = log {k(y + 1)(ex + 1)}✓
- 3y + 1 = ex + 1 + k
- 4(y + 1) = k(ex + 1)
Correct answer
y = log {k(y + 1)(ex + 1)}
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