Mathematics · Differential Equations
The general solution of the differential equation dydx = 2xyx2 - 2y - 1 is:
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- 1y2 + 2x loge y - cx - 1 = 0
- 2x2 - 2y loge y + cy - 1 = 0
- 3x2 + y loge y + cy + 1 = 0
- 4x2 + 2y loge y - cy - 1 = 0✓
Correct answer
x2 + 2y loge y - cy - 1 = 0
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