Mathematics · Difference Equations
The general solution of the difference equation yk+1 = Ayk + B, where k = 0, 1, 2, ..., A and B are constants, and A ≠ 1, is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Ayk = Aky0 + Bk(1 - Ak)1 - Ak)
- 2yk = Ayk-1 + B(1 - Ak)1 - A
- 3yk = Aky0 + B(1 - Ak)1 - A✓
- 4yk = Byk + y0
Correct answer
yk = Aky0 + B(1 - Ak)1 - A
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