Mathematics · Simple Harmonic Motion
The force (F in newtons) acting on a particle of mass 90 g executing simple harmonic motion is given by F + 0.04π2y = 0, where y is the displacement of the particle in meters. If the amplitude of the particle is 6π m, then the maximum velocity of the particle is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 14 m/s✓
- 28 m/s
- 32 m/s
- 46 m/s
Correct answer
4 m/s
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