Computer · Strength of Materials
The expression for Euler's crippling load (P) when both ends of the column are hinged/pinned is given by (where l = actual length of column, E = Young's Modulus of elasticity, I = minimum Moment of Inertia):
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1P = (EIπ2) / l2✓
- 2P = (2EIπ2) / l2
- 3P = (4EIπ2) / l2
- 4P = (EIπ2) / (4l2)
Correct answer
P = (EIπ2) / l2
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Computer?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Strength of Materials MCQs →Want more practice questions on Strength of Materials?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Computer · Strength of Materials