Physics · Heat Transfer
The equivalent thermal conductivity of a composite slab made of two materials 'a' and 'b' connected in series, having thermal conductivities Ka and Kb with equal thickness and cross-sectional area, is given by:
- 12KaKbKa + Kb✓
- 2Ka + KbKaKb
- 3KaKb
- 4Ka + Kb
Correct answer
2KaKbKa + Kb
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