Mathematics · Conic Sections

The equation of the hyperbola with eccentricity 32 and foci at (± 2, 0) is:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

1None of these
2x24 − y29 = 1
3x29 − y29 = 49
4x24 − y25 = 49✓

Correct answer

x24 − y25 = 49

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The equation of the hyperbola with eccentricity 32 and foci at (± 2, 0) is:

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