Mathematics · Coordinate Geometry
The equation of the circle passing through the point (4, 5) and having its centre at (2, 2) is:
- 1x2 + y2 + 4x + 4y - 5 = 0
- 2x2 + y2 - 4x - 4y - 5 = 0✓
- 3x2 + y2 - 4x = 13
- 4x2 + y2 - 4x - 4y + 5 = 0
Correct answer
x2 + y2 - 4x - 4y - 5 = 0
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