Mathematics · Circle
The equation of the circle in the first quadrant touching both coordinate axes at a distance of one unit from the origin is:
- 1x2 + y2 - 2x + 2y - 1 = 0
- 2x2 + y2 - 2x - 2y = 0
- 3x2 + y2 - 2x - 2y - 1 = 0
- 4x2 + y2 - 2x - 2y + 1 = 0✓
Correct answer
x2 + y2 - 2x - 2y + 1 = 0
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