Mathematics · Circle
The equation of a circle which passes through the point (3, 6) and touches both coordinate axes in the first quadrant is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1x2 + y2 - 6x - 6y + 9 = 0
- 2x2 + y2 - 30x - 30y + 225 = 0
- 3Both A and B are correct equations of such circles✓
- 4x2 + y2 - 9x - 9y + 18 = 0
Correct answer
Both A and B are correct equations of such circles
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