Mathematics · Coordinate Geometry
The equation of a circle that passes through the points (3, 0) and (0, -2) and whose centre lies on the line 2x + 3y = 3 is given by:
- 110x2 + 10y2 + 6x + 16y - 72 = 0
- 25x2 + 5y2 + 6x + 16y + 72 = 0
- 310x2 + 10y2 - 6x - 16y - 72 = 0✓
- 4x2 + y2 + 2x + 16y + 72 = 0
Correct answer
10x2 + 10y2 - 6x - 16y - 72 = 0
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Coordinate Geometry?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Coordinate Geometry