Chemistry · Statistical Thermodynamics
The entropy in terms of internal energy {U - U(0)} and canonical partition function (Q) is given by S = U - U(0) T + k ln Q. Assuming that the atoms are distinguishable, the corresponding expression for a monatomic perfect gas is: [Here n, m, N A , k, and h represent the number of moles, the mass of the atom, the Avogadro constant, Boltzmann constant, and Planck constant, respectively. U(0) is internal energy at T = 0].
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- 1S = 3 2 nR + nR ln V(2πmkT) 3/2 nN A h 3
- 2S = 5 2 nR + nR ln V(2πmkT) 3/2 h 3
- 3S = 3 2 nR + nR ln V(2πmkT) 3/2 h 3✓
- 4S = 5 2 nR + nR ln V(2πmkT) 3/2 nN A h 3
Correct answer
S = 3 2 nR + nR ln V(2πmkT) 3/2 h 3
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