Physics · Electromagnetic Waves
The electric fields of two plane electromagnetic waves in vacuum are given by E1→ = E0 ĵ cos(ωt - kx) and E2→ = E0 k̂ cos(ωt - ky). At t = 0, a particle of charge q is at the origin with a velocity v→ = 0.8c ĵ (where c is the speed of light in vacuum). The instantaneous force experienced by the particle is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1E0q (0.8 î + ĵ + 0.2 k̂)
- 2E0q (-0.8 î + ĵ + k̂)
- 3E0q (0.4 î - 3 ĵ + 0.8 k̂)
- 4E0q (0.8 î - ĵ + 0.4 k̂)✓
Correct answer
E0q (0.8 î - ĵ + 0.4 k̂)
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