Physics · Electromagnetic Waves

The electric field of an electromagnetic wave is given by E = i √2 sin(kz - ωt) V/m. The average flow of energy per unit area per unit time (average intensity) due to this wave is:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

12.7 × 10 2 W/m 2
22.7 × 10 -2 W/m 2
32.7 × 10 -9 W/m 2✓
42.7 × 10 4 W/m 2

Correct answer

2.7 × 10 -9 W/m 2

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The electric field of an electromagnetic wave is given by E = i √2 sin(kz - ωt) V/m. The average flow of energy per unit area per unit time (average intensity) due to this wave is:

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The electric field of an electromagnetic wave is given by E = i &radic;2 sin(kz - &omega;t) V/m. The average flow of energy per unit area per unit time (average intensity) due to this wave is:

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The electric field of an electromagnetic wave is given by E = i √2 sin(kz - ωt) V/m. The average flow of energy per unit area per unit time (average intensity) due to this wave is: