Mathematics · Functions
The domain and range of the real-valued function f(x) = 1√(|x| - x2) are A and B respectively. Then A ∪ B is equal to:
- 1(-1, 0) ∪ (0, 1) ∪ [2, ∞)✓
- 2ℝ - {-1, 0, 1}
- 3(-1, 1) ∪ [2, ∞)
- 4(-1, ∞) - {0, 1}
Correct answer
(-1, 0) ∪ (0, 1) ∪ [2, ∞)
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