Mathematics · Differential Equations
The differential equation of all circles which pass through the origin and whose centers lie on the Y-axis is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1(x2 - y2)dydx - 2xy = 0
- 2(x2 - y2)dydx + 2xy = 0✓
- 3(x2 - y2)dydx + xy = 0
- 4(x2 - y2)dydx - xy = 0
Correct answer
(x2 - y2)dydx + 2xy = 0
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