Mathematics · Differential Equations
The differential equation for which y2 = 4a(x + a) (where 'a' is a parameter) is the general solution is:
- 1y = 2x dydx + y (dydx)2✓
- 2y = y dydx - x (dydx)2
- 3x = 3 dydx + y (dydx)2
- 4y = 3x2 dydx + y2 (dydx)2
Correct answer
y = 2x dydx + y (dydx)2
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