Physics · Dual Nature of Matter
The de-Broglie wavelength of an electron moving with speed v is the same as that of a photon moving in free space. Let Ee and Pe refer to the kinetic energy and linear momentum of the electron respectively, and Ep and Pp refer to the energy and linear momentum of the photon respectively. Which of the following relations is correct? (c is the velocity of light in free space)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1PePp = v2c
- 2PePp = 2cv
- 3EeEp = v2c✓
- 4EeEp = 2cv
Correct answer
EeEp = v2c
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