Physics · Center of Gravity
The center of gravity of a trapezium with parallel sides A and B (where side B is at the base) and height H, measured from the base B, is at a distance of:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1H(B - 2A) B + A
- 2H(B - 2A) 3(B + A)
- 3H(B + 2A) 3(B + A)✓
- 4H(B - 2A) 2(B + A)
Correct answer
H(B + 2A) 3(B + A)
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