Physics · Nuclear Physics
The binding energy changes for the following nuclear reactions are given in MeV: 32He + 10n → 42He + 20 MeV42He + 10n → 52He - 0.9 MeV If X3, X4, and X5 denote the stability of 32He, 42He, and 52He respectively, then the correct order of stability is:
- 1X4 < X5 < X3
- 2X4 > X5 < X3
- 3X4 = X5 = X3
- 4X4 > X5 > X3✓
Correct answer
X4 > X5 > X3
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