Mathematics · Partial Differential Equations
Solve the partial differential equation ∂u∂x + 2∂u∂y = 0, subject to the Cauchy condition u = sin(x) on y = 3x + 1.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1u = sin(2x + y - 1)
- 2u = sin(x + 2y - 1)
- 3u = -sin(x + y + 1)
- 4u = -sin(2x - y + 1)✓
Correct answer
u = -sin(2x - y + 1)
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