Mathematics · Differential Equations
Solve the initial value problem d2xdt2 + 4x = 0, with x(0) = 1, x'(0) = 0.
- 1x = cos 2t - sin 2t
- 2x = cos 2t + sin 2t
- 3x = cos 2t✓
- 4x = sin 2t
Correct answer
x = cos 2t
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