Mathematics · Boolean Algebra
Simplify the following Boolean expression using De Morgan's theorem: f(A, B, C, D, E, F) = ((A + B)C'D' + (E' + F'))'
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1(A B C + D E F)'
- 2(A' B' + C + D) E F✓
- 3(A B' + C' D + E F)'
- 4(A' + B' + C')(D' + E' + F')
Correct answer
(A' B' + C + D) E F
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